Almost all of today's class was spent discussing how to solve equations that possess terms with more than one denominator. We came to the conclusion that we needed to find the Lowerst Common Multiple of all the denominators and then multiply the LCM against each term in the problem. This allowed us to cancel off the denominators or each term and then solve the problems like we had before.
For notes and examples click here.
Homework for tomorrow was to finish the example we started in class.
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